HEAT ENGINEERING
CONTENTS CHAPTER 1 - SECTION A - MATHCAD SOLUTIONS CHAPTER 2 - SECTION A - MATHCAD SOLUTIONS CHAPTER 3 - SECTION A - MATHCAD SOLUTIONS CHAPTER 4 - SECTION A - MATHCAD SOLUTIONS CHAPTER 5 - SECTION A - MATHCAD SOLUTIONS CHAPTER 6 - SECTION A - MATHCAD SOLUTIONS CHAPTER 7 - SECTION A - MATHCAD SOLUTIONS CHAPTER 8 - SECTION A - MATHCAD SOLUTIONS CHAPTER 9 - SECTION A - MATHCAD SOLUTIONS CHAPTER 10 - SECTION A - MATHCAD SOLUTIONS CHAPTER 11 - SECTION A - MATHCAD SOLUTIONS CHAPTER 12 - SECTION A - MATHCAD SOLUTIONS CHAPTER 13 - SECTION A - MATHCAD SOLUTIONS CHAPTER 14 - SECTION A - MATHCAD SOLUTIONS CHAPTER 15 - SECTION A - MATHCAD SOLUTIONS CHAPTER 16 - SECTION A - MATHCAD SOLUTIONS CHAPTER 1 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 2 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 3 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 4 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 5 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 6 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 7 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 8 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 9 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 10 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 11 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 12 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 13 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 14 - SECTION B - NON-NUMERICAL SOLUTIONS CHAPTER 16 - SECTION B - NON-NUMERICAL SOLUTIONS P 3000ATM D 017IN A S ˜ H 2562IN PATM 2986IN_HG PABS U G ˜ H ˜ PATM PABS 2722PSIA ANS CHAPTER 1 - SECTION A - MATHCAD SOLUTIONS 14 THE EQUATION THAT RELATES DEG F TO DEG C IS: T(F) = 18 T(C) + 32 SOLVE THIS EQUATION BY SETTING T(F) = T(C) GUESS SOLUTION: T GIVEN T 18T = FIND T( ) ANS 15 BY DEFINITION: P F A = F MASS G ˜ = NOTE: PRESSURES ARE IN GAUGE PRESSURE P 3000BAR D 4MM A S MASS F G MASS 3844KG ANS 16 BY DEFINITION: P F A = F MASS G ˜ = FMARS K X ˜ FMARS U MK GMARS FMARS MASS GMARS 001 MK KG ANS 112 GIVEN: Z P D D U G ˜ = AND: U M P ˜ R T ˜ = SUBSTITUTING: Z P D D M P ˜ R T ˜ G ˜ = SEPARATING VARIABLES AND INTEGRATING: PSEA PDENVER P P ´µ µ¶ D X 108CM F MASS G ˜ F 3924N KS F X KS 363333 N M ON MARS: X 040CM COSTBULB 500DOLLARS 1000HR ˜ HR DAY COSTELEC 01DOLLARS KW HR ˜ ˜ HR DAY R 8206 CM3 ATM ˜ MOL K ˜ T M 'LEARTH LBM ˜ M 113498LBM MASS 1250KG U 40 M S EK 'H 50M PATM 3012IN_HG A S PATM 10157KPA A S U N TON 29 MJ KG ˜ COST_COAL 095GJ ˜ COST_GASOLINE 1428GJ KW HR ˜ COST_ELECTRICITY 27778GJ B)THE ELECTRICAL ENERGY CAN DIRECTLY BE CONVERTED TO OTHER FORMS OF ENERGY WHEREAS THE COAL AND GASOLINE WOULD TYPICALLY NEED TO BE CONVERTED TO HEAT AND THEN INTO SOME OTHER FORM OF ENERGY BEFORE BEING USEFUL THE OBVIOUS ADVANTAGE OF COAL IS THAT IT IS CHEAP IF IT IS USED AS A HEAT SOURCE OTHERWISE IT IS MESSY TO HANDLE AND BULKY FOR TRANPORT AND STORAGE GASOLINE IS AN IMPORTANT TRANSPORTATION FUEL IT IS MORE CONVENIENT TO TRANSPORT AND STORE THAN COAL IT CAN BE USED TO GENERATE ELECTRICITY BY BURNING IT BUT THE EFFICIENCY IS LIMITED HOWEVER, FUEL CELLS ARE CURRENTLY BEING DEVELOPED WHICH WILL ALLOW FOR THE CONVERSION OF GASOLINE TO ELECTRICITY BY CHEMICAL MEANS, A MORE EFFICIENT PROCESS ELECTRICITY HAS THE MOST USES THOUGH IT IS EXPENSIVE IT IS EASY TO TRANSPORT BUT EXPENSIVE TO STORE AS A TRANSPORTATION FUEL IT IS CLEAN BUT BATTERIES TO STORE IT ON-BOARD HAVE LIMITED CAPACITY AND ARE HEAVY HEAT ENGINEERING 124 USE THE MATCAD GENFIT FUNCTION TO FIT THE DATA TO ANTOINE'S EQUATION THE GENFIT FUNCTION REQUIRES THE FIRST DERIVATIVES OF THE FUNCTION WITH RESPECT TO THE PARAMETERS BEING FITTED FUNCTION BEING FIT: F T A B C ( ) E A B T C §¨© · ¹ FIRST DERIVATIVE OF THE FUNCTION WITH RESPECT TO PARAMETER A A F T A B C ( ) D D EXP A B T C §¨© · ¹ O FIRST DERIVATIVE OF THE FUNCTION WITH RESPECT TO PARAMETER B B F T A B C ( ) D D §¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨ ¨© · ¸ ¸ ¸ ¸ ¸ ¸ ¸ ¸ ¸ ¸ ¸ ¹ §¨© · ¹ §¨© · ¹ ˜ ª " " " " " " " " " ¬ º" " " " " " " " " " ¼ GUESS